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Popular Functions >

midpoint (0,-10),(1,-3)

Solution

midpoint

(0, - 10), (1, - 3)

Solution

(\frac{1}{2}, - \frac{13}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (0, - 10), (x_{2}, y_{2}) = (1, - 3)

= (\frac{1 + 0}{2}, \frac{- 3 - 10}{2})

Refine

= (\frac{1}{2}, - \frac{13}{2})

Graph

Popular Examples

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sy mm e t ry x^{4} - x^{2}

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d o main f (x) = 9 - 4 x^{2}

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d o main f (x) = \frac{( 2 - x )}{x + 3}

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p er i o d i c i t y 3 + t^{5} + sin (π t)

range of 1/4 x^3-6

r an g e \frac{1}{4} x^{3} - 6

Frequently Asked Questions (FAQ)

What is the midpoint (0,-10),(1,-3) ?
The midpoint (0,-10),(1,-3) is (1/2 ,-13/2)