What is the domain of f(x)=(2x^2+3)/(4x^3+1) ?

The domain of f(x)=(2x^2+3)/(4x^3+1) is x -1/(\sqrt[3]{4)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=(2x^2+3)/(4x^3+1)

domain

f (x) = \frac{2 x ^{2} + 3}{4 x ^{3} + 1}

x < - \frac{1}{3 4} or x > - \frac{1}{3 4}

Interval Notation

(- \infty, - \frac{1}{3 4}) \cup (- \frac{1}{3 4}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{3 4}

The function domain

x < - \frac{1}{3 4} or x > - \frac{1}{3 4}

a sy m pt o t es \frac{2 x - 4}{x ^{2} + x - 2}

l in e (25, 1), (30, 0)

d o main f (x) = 2 x + 1

d o main f (x) = \frac{2 x + 12}{3 x}

d o main f (x) = arctan (1 + e^{- r^{2}})

What is the domain of f(x)=(2x^2+3)/(4x^3+1) ?
The domain of f(x)=(2x^2+3)/(4x^3+1) is x<-1/(\sqrt[3]{4)}\lor x>-1/(\sqrt[3]{4)}