What is the domain of (-7)/(2x^{3/2)} ?

The domain of (-7)/(2x^{3/2)} is x>0

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domain of (-7)/(2x^{3/2)}

domain

\frac{- 7}{2 x ^{\frac{3}{2}}}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

p er i o d i c i t y f (x) = 3 sin (\frac{6 x}{7} + 2 π)

d o main \frac{x + 6}{x - 5}

d o main x + 1

in v erse f (x) = 3 x^{2} - 8

in v erse f (x) = \frac{3 x + 4}{- 5 x - 7}