What is the shift 0.02sin(0.02x+1.59)+1 ?

The shift 0.02sin(0.02x+1.59)+1 is Phase:-79.5, Vertical:1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

shift 0.02sin(0.02x+1.59)+1

shift

Phase : - 79.5, Vertical : 1

Solution steps

f (x) = 0.02 sin (0.02 x + 1.59) + 1

g (B x - C) = sin (0.02 x + 1.59), B = 0.02, C = - 1.59, D = 1

Therefore, the phase shift

\frac{C}{B}

\frac{- 1.59}{0.02}

- 79.5

The vertical shift

D

1

1

What is the shift 0.02sin(0.02x+1.59)+1 ?
The shift 0.02sin(0.02x+1.59)+1 is Phase:-79.5, Vertical:1