What is the perpendicular y=-4/3 x-3,(-4,1) ?

The perpendicular y=-4/3 x-3,(-4,1) is y= 3/4 x+4

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perpendicular y=-4/3 x-3,(-4,1)

perpendicular

y = - \frac{4}{3} x - 3, (- 4, 1)

y = \frac{3}{4} x + 4

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{4}{3} x - 3

that passes through

(- 4, 1)

Find the slope of

y = - \frac{4}{3} x - 3 : m = - \frac{4}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(- 4, 1) : y = \frac{3}{4} x + 4

y = \frac{3}{4} x + 4

(1) (1)

f (x) = \frac{x}{1 + 2 x}

9 + 1 + x

tan (e^{3 t}) + e^{t a n (3 t)}

\frac{1}{- 5 x + 8}

What is the perpendicular y=-4/3 x-3,(-4,1) ?
The perpendicular y=-4/3 x-3,(-4,1) is y= 3/4 x+4