What is the domain of f(x)=sqrt(x+1) ?

The domain of f(x)=sqrt(x+1) is x>=-1

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domain of f(x)=sqrt(x+1)

domain

f (x) = x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

a sy m pt o t es f (x) = \frac{( x - 2 )}{x - 9}

e x t re m e f (x) = x^{3} - 3 x + 4

in t erce pt s f (x) = 2 x^{2} - 5 x + 7

d o main f (x) = 4 x - 5

in v erse y = 2 x - 9