What is the domain of f(x)=sqrt(2x+1) ?

The domain of f(x)=sqrt(2x+1) is x>=-1/2

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domain of f(x)=sqrt(2x+1)

domain

f (x) = 2 x + 1

x \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

The function domain

x \geq - \frac{1}{2}

e x t re m e \frac{x ^{3}}{x ^{2} - 4}

p a r i t y f (x) = x^{4} - 2 x^{2}

in v erse \frac{3 x - 1}{2 x + 5}

in v erse y = (x + 4)^{3}

in v erse f (x) = 1 0^{x - 2}

What is the domain of f(x)=sqrt(2x+1) ?
The domain of f(x)=sqrt(2x+1) is x>=-1/2