What is the range of-cos(2x) ?

The range of-cos(2x) is -1<= f(x)<= 1

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range of-cos(2x)

range

- cos (2 x)

- 1 \leq f (x) \leq 1

Interval Notation

[- 1, 1]

Solution steps

The range of the basic

cos

function is

- 1 \leq cos (2 x) \leq 1

- 1 \leq cos (2 x) \leq 1

Multiply the edges of the range by:

- 1

- 1 \leq - cos (2 x) \leq 1

Therefore the range is

- 1 \leq f (x) \leq 1

s l o p e y = - \frac{4}{5} x + \frac{1}{2}

d i s t an ce (- 1, 8), (2, 3)

in t erce pt s f (x) = 2 x

s hi f t - 2 + 2 cos (2 x - \frac{π}{2})

d o main f (x) = 3 x^{3} - 4 x + \frac{1}{3}