斜率 11x+6y=3

解答

斜率

11 x + 6 y = 3

m = - \frac{11}{6}

求解步骤

斜率标准形式:

m = - \frac{11}{6}

m = - \frac{11}{6}

p a r i t y - \frac{1 - cos ( 4 x )}{1 + cos ( 4 x )}

in v erse h (t) = - 4.9 (t + 3)^{2} + 45.8

in t erce pt s f (x) = \frac{6 x - 1}{2 x + 2}

sy mm e t ry x = 4 (y - 1)^{2}

d o main y = \frac{e ^{x} - 1}{x}