What is the inverse of f(x)=2x^2+3 ?

The inverse of f(x)=2x^2+3 is sqrt((x-3)/2),-sqrt((x-3)/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=2x^2+3

inverse

f (x) = 2 x^{2} + 3

\frac{x - 3}{2}, - \frac{x - 3}{2}

Solution steps

y = 2 x^{2} + 3

Replace

x

with

y

x = 2 y^{2} + 3

Solve for

y, x = 2 y^{2} + 3

\frac{x - 3}{2}, - \frac{x - 3}{2}

p a r i t y 2 x + 4

s l o p e in t erce pt \frac{1}{5} y = x - \frac{1}{5}

m o n o t o n e f (x) = \frac{x}{x - 1}

s l o p e f (x) = 3 - 2 x e n e l (- 1.5)

r an g e \frac{x ^{2} + 12}{3}

What is the inverse of f(x)=2x^2+3 ?
The inverse of f(x)=2x^2+3 is sqrt((x-3)/2),-sqrt((x-3)/2)