What is the critical f(x)=5x^2+4x ?

The critical f(x)=5x^2+4x is x=-2/5

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critical f(x)=5x^2+4x

critical points

f (x) = 5 x^{2} + 4 x

x = - \frac{2}{5}

Solution steps

5 x^{2} + 4 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{5}

Identify critical points not in

f (x)

domain

Domain of

5 x^{2} + 4 x : - \infty < x < \infty

All critical points are in domain

x = - \frac{2}{5}

3 x - 8

y = \frac{1}{x + 1}

f (x) = \frac{1}{5} x - \frac{1}{6}

f (x) = (\frac{1}{2})^{x}

f (x) = \frac{x ^{2} + 5 x}{x ^{2} + 7 x + 10}