What is the monotone f(x)= 1/(4x^2+8) ?

The monotone f(x)= 1/(4x^2+8) is Increasing:-infinity <x<0,Decreasing:0<x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

monotone f(x)= 1/(4x^2+8)

monotone intervals

f (x) = \frac{1}{4 x ^{2} + 8}

Increasing : - \infty < x < 0, Decreasing : 0 < x < \infty

Solution steps

f^{'} (x) = - \frac{x}{2 ( x ^{2} + 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Increasing : - \infty < x < 0, Decreasing : 0 < x < \infty

d o main \frac{1}{2}

p a r a ll e l y = \frac{2}{3} x + 7 (6.4)

a sy m pt o t es f (x) = \frac{x ^{3} + 4 x - 2}{x ^{2} - 4}

in v erse f (x) = (x - 4)

d o main f (x) = \frac{3 x - 4}{x ^{3} - 4}

What is the monotone f(x)= 1/(4x^2+8) ?
The monotone f(x)= 1/(4x^2+8) is Increasing:-infinity <x<0,Decreasing:0<x<infinity