What is the perpendicular y=-1/3 x+9 ?

The perpendicular y=-1/3 x+9 is y=3x+b

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perpendicular y=-1/3 x+9

perpendicular

y = - \frac{1}{3} x + 9

y = 3 x + b

Solution steps

Find the slope of

y = - \frac{1}{3} x + 9 : m = - \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = 3

Line with slope m=

3 : y = 3 x + b

y = 3 x + b

in v erse f (x) = 3 x + 2

in v erse y = \frac{4}{x + 3}

in v erse f (x) = \frac{6}{x + 3}

a sy m pt o t es r (x) = \frac{6 x ^{2} + 1}{2 x ^{2} + x - 1}

s hi f t f (x) = 5 sin (4 x + 2 π)