What is the inverse of f(x)=9x^2+8x+6 ?

The inverse of f(x)=9x^2+8x+6 is (-4+sqrt(9x-38))/9 ,-(sqrt(9x-38)+4)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=9x^2+8x+6

inverse

f (x) = 9 x^{2} + 8 x + 6

\frac{- 4 + 9 x - 38}{9}, - \frac{9 x - 38 + 4}{9}

Solution steps

y = 9 x^{2} + 8 x + 6

Replace

x

with

y

x = 9 y^{2} + 8 y + 6

Solve for

y, x = 9 y^{2} + 8 y + 6

\frac{- 4 + 9 x - 38}{9}, - \frac{9 x - 38 + 4}{9}

s l o p e in t erce pt (4 - 9) - 5

in v erse f (x) = 1 + 4 + 5 x

a sy m pt o t es f (x) = \frac{x ^{3}}{x ^{2} - 1}

f (x) = x - 5

d o main f (x) = (\frac{1 - 5 x}{3 + x})

What is the inverse of f(x)=9x^2+8x+6 ?
The inverse of f(x)=9x^2+8x+6 is (-4+sqrt(9x-38))/9 ,-(sqrt(9x-38)+4)/9