What is the slope ofintercept (y+2)= 1/3 (x+9) ?

The slope ofintercept (y+2)= 1/3 (x+9) is y= 1/3 x+1

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slope ofintercept (y+2)= 1/3 (x+9)

slope intercept

(y + 2) = \frac{1}{3} (x + 9)

y = \frac{1}{3} x + 1

Solution steps

y + 2 = \frac{1}{3} (x + 9)

Convert to slope intercept form:

y = \frac{1}{3} x + 1

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = \frac{1}{3} x + 1

in v erse f (x) = \frac{5 x}{4}

d o main 6 x^{3} + \frac{9}{x}

d o main f (x) = ln (5 - 2 x)

in v erse f (x) = \frac{3 x - 4}{x + 2}

d o main f (x) = \frac{8}{x}

What is the slope ofintercept (y+2)= 1/3 (x+9) ?
The slope ofintercept (y+2)= 1/3 (x+9) is y= 1/3 x+1