What is the domain of 1/(sqrt(x+9)) ?

The domain of 1/(sqrt(x+9)) is x>-9

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domain of 1/(sqrt(x+9))

domain

\frac{1}{x + 9}

x > - 9

Interval Notation

(- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = - 9

Combine real regions and undefined points for final function domain

x > - 9

p er p e n d i c u l a r y = - 4 x + 3

cr i t i c a l x^{2} e^{15 x}

in v erse \frac{9 x}{3 - x}

in t erce pt s f (x) = \frac{2 x}{x - 3}

s im pl i f y (7.7) (10.1)