What is the domain of f(x)=\sqrt[4]{x+9} ?

The domain of f(x)=\sqrt[4]{x+9} is x>=-9

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domain of f(x)=\sqrt[4]{x+9}

domain

f (x) = 4 x + 9

x \geq - 9

Interval Notation

[- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

The function domain

x \geq - 9

e x t re m e f (x) = x^{3} - 9 x^{2} - 120 x + 6

d o main f (x) = ∣ 9 - x ∣

r an g e 4 x - 2 - 8

r an g e 2 e^{x} + 1

p a r i t y f (x) = x^{3} + 2 x^{2} + 1

What is the domain of f(x)=\sqrt[4]{x+9} ?
The domain of f(x)=\sqrt[4]{x+9} is x>=-9