What is the inverse of f(x)=((x+2))/((2x+1)) ?

The inverse of f(x)=((x+2))/((2x+1)) is (2-x)/(2x-1)

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inverse of f(x)=((x+2))/((2x+1))

inverse

f (x) = \frac{( x + 2 )}{( 2 x + 1 )}

\frac{2 - x}{2 x - 1}

Solution steps

y = \frac{x + 2}{2 x + 1}

Replace

x

with

y

x = \frac{y + 2}{2 y + 1}

Solve for

y, x = \frac{y + 2}{2 y + 1}

\frac{2 - x}{2 x - 1}

sy mm e t ry y = x^{2} - 5 x + 6

d o main x - 12

d o main f (x) = \frac{7 z + 6}{z - 7} + \frac{7 z + 3}{z - 7}

in v erse f (x) = (x - 2)^{2} + 3

d o main f (x) = \frac{- 5 x}{- 2 x - 3}

What is the inverse of f(x)=((x+2))/((2x+1)) ?
The inverse of f(x)=((x+2))/((2x+1)) is (2-x)/(2x-1)