What is the asymptotes of f(x)=(x^2+x-6)/(x^3-1) ?

The asymptotes of f(x)=(x^2+x-6)/(x^3-1) is Vertical: x=1,Horizontal: y=0

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asymptotes of f(x)=(x^2+x-6)/(x^3-1)

asymptotes

f (x) = \frac{x ^{2} + x - 6}{x ^{3} - 1}

Vertical : x = 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} + x - 6}{x ^{3} - 1} : x = 1

Horizontal Asymptotes of

\frac{x ^{2} + x - 6}{x ^{3} - 1} : y = 0

Slant Asymptotes of

\frac{x ^{2} + x - 6}{x ^{3} - 1} :

None

Vertical : x = 1, Horizontal : y = 0

f (x) = - x - 7

f (x) = 6 x^{4} - x^{3} - 25 x^{2} + 4 x + 4

\frac{x ^{2} + 4}{x}

f (x) = \frac{2 x ^{2} + 10 x + 12}{x ^{2} + 3 x + 2}

f (x) = \frac{e ^{x}}{3 + e ^{x}}

What is the asymptotes of f(x)=(x^2+x-6)/(x^3-1) ?
The asymptotes of f(x)=(x^2+x-6)/(x^3-1) is Vertical: x=1,Horizontal: y=0