What is the inverse of 2+\sqrt[3]{2-3x} ?

The inverse of 2+\sqrt[3]{2-3x} is -(x^3-6x^2+12x-10)/3

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inverse of 2+\sqrt[3]{2-3x}

inverse

2 + 3 2 - 3 x

- \frac{x ^{3} - 6 x ^{2} + 12 x - 10}{3}

Solution steps

y = 2 + 3 2 - 3 x

Replace

x

with

y

x = 2 + 3 2 - 3 y

Solve for

y, x = 2 + 3 2 - 3 y

- \frac{x ^{3} - 6 x ^{2} + 12 x - 10}{3}

p a r i t y x (sec^{2} (2 x) \cdot 2)

d o main f (x) = \frac{5}{2 x}

s im pl i f y (- 1.5) (7.9)

l in e m = \frac{2}{9}, (9, 0)

s l o p e 12 x + 4 y = 47

What is the inverse of 2+\sqrt[3]{2-3x} ?
The inverse of 2+\sqrt[3]{2-3x} is -(x^3-6x^2+12x-10)/3