What is the midpoint (1/2 , 1/3),(3/2 ,(-5)/3) ?

The midpoint (1/2 , 1/3),(3/2 ,(-5)/3) is (1,-2/3)

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midpoint (1/2 , 1/3),(3/2 ,(-5)/3)

midpoint

(\frac{1}{2}, \frac{1}{3}), (\frac{3}{2}, \frac{- 5}{3})

(1, - \frac{2}{3})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (\frac{1}{2}, \frac{1}{3}), (x_{2}, y_{2}) = (\frac{3}{2}, \frac{- 5}{3})

= (\frac{\frac{3}{2} + \frac{1}{2}}{2}, \frac{\frac{- 5}{3} + \frac{1}{3}}{2})

Refine

= (1, - \frac{2}{3})

e x t re m e f (x) = 2.2 + 2.2 x - 0.6 x^{2}

d o main f (x) = 3 x - 12

d o main f (x) = e^{x}

e x t re m e \frac{x}{2} + cos (x)

in v erse f (x) = 8 (x - 8)^{3}

What is the midpoint (1/2 , 1/3),(3/2 ,(-5)/3) ?
The midpoint (1/2 , 1/3),(3/2 ,(-5)/3) is (1,-2/3)