值域 sqrt(-x+3)

解答

值域

- x + 3

f (x) \geq 0

间隔符号

[0, \infty)

求解步骤

c a x + b + k

形式的根函数的值域为

f (x) \geq k

k = 0

f (x) \geq 0

mi d p o in t (2, - 1), (4, 5)

e x t re m e f (x) = \frac{( x - 1 ) ^{2}}{x ^{2} + 2}

l in e (0, 2017.92), (350, 8142.92)

e x t re m e e^{x} - e^{2 x}

p er i o d i c i t y f (x) = cos (\frac{π}{8} n^{2})