What is the inverse of f(x)=\sqrt[3]{x}+8 ?

The inverse of f(x)=\sqrt[3]{x}+8 is x^3-24x^2+192x-512

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inverse of f(x)=\sqrt[3]{x}+8

inverse

f (x) = 3 x + 8

x^{3} - 24 x^{2} + 192 x - 512

Solution steps

y = 3 x + 8

Replace

x

with

y

x = 3 y + 8

Solve for

y, x = 3 y + 8

x^{3} - 24 x^{2} + 192 x - 512

p a r i t y f (x) = - x^{4} - 2 x

e x t re m e x^{4} - x^{2}

d o main x^{2} - 4 x + 3

p a r i t y y = sec (θ) (θ - tan (θ))

a sy m pt o t es f (x) = \frac{1}{x + 2} - 3

What is the inverse of f(x)=\sqrt[3]{x}+8 ?
The inverse of f(x)=\sqrt[3]{x}+8 is x^3-24x^2+192x-512