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range of f(x)=x^2(x-6)range of f(x)= 1/(1-\frac{1){(x-2)}}asymptotes of (x^2-9x+39)/(x-7)domain of f(x)=(sqrt(x+3))^2intercepts of (3(x-2))/(2(x-2))

Frequently Asked Questions (FAQ)

  • What is the inverse of f(x)=\sqrt[3]{x-9}+1 ?

    The inverse of f(x)=\sqrt[3]{x-9}+1 is x^3-3x^2+3x+8