en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Functions >

range of-490t^2+75t+12

Solution

range

Solution

f (t) \leq \frac{5829}{392}

+1

Interval Notation

Solution steps

Vertex of

- 490 t^{2} + 75 t + 12 :

Maximum

(\frac{15}{196}, \frac{5829}{392})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 490,

Vertex

(x_{v}, y_{v}) = (\frac{15}{196}, \frac{5829}{392})

f (t) \leq \frac{5829}{392}

Graph

Popular Examples

inverse of (x-2)^2-7

range of-1/(x+1)

domain of f(x)=sqrt(-3x+1)

domain of e^{1/x}

Frequently Asked Questions (FAQ)

What is the range of-490t^2+75t+12 ?
The range of-490t^2+75t+12 is f(t)<= 5829/392