What is the inverse of sqrt(x^2-3x+2) ?

The inverse of sqrt(x^2-3x+2) is (3+sqrt(4x^2+1))/2 ,(3-sqrt(4x^2+1))/2

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inverse of sqrt(x^2-3x+2)

inverse

\frac{3 + 4 x ^{2} + 1}{2}, \frac{3 - 4 x ^{2} + 1}{2}

Solution steps

y = x^{2} - 3 x + 2

Replace

x

with

y

x = y^{2} - 3 y + 2

Solve for

y, x = y^{2} - 3 y + 2

\frac{3 + 4 x ^{2} + 1}{2}, \frac{3 - 4 x ^{2} + 1}{2}

What is the inverse of sqrt(x^2-3x+2) ?
The inverse of sqrt(x^2-3x+2) is (3+sqrt(4x^2+1))/2 ,(3-sqrt(4x^2+1))/2