What is the domain of-7/(2t^{(3/2))} ?

The domain of-7/(2t^{(3/2))} is t>0

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domain of-7/(2t^{(3/2))}

domain

- \frac{7}{2 t ^{(\frac{3}{2})}}

t > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 0

Find undefined (singularity) points:

t = 0

Combine real regions and undefined points for final function domain

t > 0

d o main f (x) = \frac{x}{x ^{2} - 1}

a sy m pt o t es f (x) = - \frac{3}{x - 2}

r an g e f (x) = \frac{1}{2 x ^{2} - x - 6}

d i s t an ce (0, 7), (4, 6)

d o main f (x) = 3 \frac{x}{x ^{2} + 6 x - 16}