extreme f(x)=4x^3-15x^2-18x+7

Lösung

extrempunkte

f (x) = 4 x^{3} - 15 x^{2} - 18 x + 7

Maximum (- \frac{1}{2}, \frac{47}{4}), Minimum (3, - 74)

Schritte zur Lösung

f^{'} (x) = 12 x^{2} - 30 x - 18

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{1}{2},

Absteigend

: - \frac{1}{2} < x < 3,

Ansteigend

: 3 < x < \infty

Stecke

x = - \frac{1}{2}

4 x^{3} - 15 x^{2} - 18 x + 7 : \frac{47}{4}

Maximum (- \frac{1}{2}, \frac{47}{4})

Stecke

x = 3

4 x^{3} - 15 x^{2} - 18 x + 7 : - 74

Minimum (3, - 74)

Maximum (- \frac{1}{2}, \frac{47}{4}), Minimum (3, - 74)

p a r i t y cot (x) cos (x) + csc (x) sin (2) (x)

e x t re m e f (x) = x^{4} - 4 x^{2} + 4

in v erse f (x) = - 3 x - 2

s l o p e in t erce pt 2 x - 3 y = - 6

in v erse 1 + ln (t)