What is the range of y=sqrt(2x-8) ?

The range of y=sqrt(2x-8) is f(x)>= 0

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range of y=sqrt(2x-8)

range

y = 2 x - 8

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

in v erse f (x) = \frac{3}{x} + 5

f (x) = x^{2} + 4 x + 1

cr i t i c a l \frac{x ^{2} + 7}{x - 4}

in v erse y = 9^{x}

d o main f (x) = 9.5 x^{2} - x + 4.3