What is the inverse of y=((-3x-7))/((x-1)) ?

The inverse of y=((-3x-7))/((x-1)) is (-7+x)/(x+3)

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inverse of y=((-3x-7))/((x-1))

inverse

y = \frac{( - 3 x - 7 )}{( x - 1 )}

\frac{- 7 + x}{x + 3}

Solution steps

y = \frac{- 3 x - 7}{x - 1}

Replace

x

with

y

x = \frac{- 3 y - 7}{y - 1}

Solve for

y, x = \frac{- 3 y - 7}{y - 1}

\frac{- 7 + x}{x + 3}

(- 1, - 5), (2, 1)

f (x) = - 2 x - 2 + 6

3 x + 15

f (x) = (\frac{1}{4} x + 6)^{3}

f (x) = \frac{9 - x}{x + 4}

What is the inverse of y=((-3x-7))/((x-1)) ?
The inverse of y=((-3x-7))/((x-1)) is (-7+x)/(x+3)