What is the domain of f(x)=(sqrt(x))/(7x^2+6x-1) ?

The domain of f(x)=(sqrt(x))/(7x^2+6x-1) is 0 1/7

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domain of f(x)=(sqrt(x))/(7x^2+6x-1)

domain

f (x) = \frac{x}{7 x ^{2} + 6 x - 1}

0 \leq x < \frac{1}{7} or x > \frac{1}{7}

Interval Notation

[0, \frac{1}{7}) \cup (\frac{1}{7}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{7}, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{7} or x > \frac{1}{7}

(0, - 7), (- 6, - 3)

f (x) = x^{\frac{2}{3}}

f (x) = 2 x - 1 3 x + 2

f (x) = \frac{( x + 7 )}{x - 5}

y = x

What is the domain of f(x)=(sqrt(x))/(7x^2+6x-1) ?
The domain of f(x)=(sqrt(x))/(7x^2+6x-1) is 0<= x< 1/7 \lor x> 1/7