What is the midpoint (-5/2 , 1/2),(-7/2 ,-9/2) ?

The midpoint (-5/2 , 1/2),(-7/2 ,-9/2) is (-3,-2)

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midpoint (-5/2 , 1/2),(-7/2 ,-9/2)

midpoint

(- \frac{5}{2}, \frac{1}{2}), (- \frac{7}{2}, - \frac{9}{2})

(- 3, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- \frac{5}{2}, \frac{1}{2}), (x_{2}, y_{2}) = (- \frac{7}{2}, - \frac{9}{2})

= (\frac{- \frac{7}{2} - \frac{5}{2}}{2}, \frac{- \frac{9}{2} + \frac{1}{2}}{2})

Refine

= (- 3, - 2)

d o main f (x) = \frac{2 x ^{2} - x - 1}{x ^{2} + 9}

in v erse f (x) = (16 - t)^{\frac{1}{8}}

r an g e - \frac{2}{x}

in v erse f (x) = 4 (x + 2)^{3}

a sy m pt o t es h (x) = \frac{1}{3} e^{x + 2} + 2

What is the midpoint (-5/2 , 1/2),(-7/2 ,-9/2) ?
The midpoint (-5/2 , 1/2),(-7/2 ,-9/2) is (-3,-2)