What is the inverse of (3x^2+13x-25)/(x+6) ?

The inverse of (3x^2+13x-25)/(x+6) is (-13+x+sqrt(x^2+46x+469))/6 ,(-13+x-sqrt(x^2+46x+469))/6

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inverse of (3x^2+13x-25)/(x+6)

inverse

\frac{- 13 + x + x ^{2} + 46 x + 469}{6}, \frac{- 13 + x - x ^{2} + 46 x + 469}{6}

Solution steps

y = \frac{3 x ^{2} + 13 x - 25}{x + 6}

Replace

x

with

y

x = \frac{3 y ^{2} + 13 y - 25}{y + 6}

Solve for

y, x = \frac{3 y ^{2} + 13 y - 25}{y + 6}

\frac{- 13 + x + x ^{2} + 46 x + 469}{6}, \frac{- 13 + x - x ^{2} + 46 x + 469}{6}

What is the inverse of (3x^2+13x-25)/(x+6) ?
The inverse of (3x^2+13x-25)/(x+6) is (-13+x+sqrt(x^2+46x+469))/6 ,(-13+x-sqrt(x^2+46x+469))/6