What is the inverse of f(x)=2\sqrt[3]{x}-4 ?

The inverse of f(x)=2\sqrt[3]{x}-4 is (x^3)/8+(3x^2)/2+6x+8

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inverse of f(x)=2\sqrt[3]{x}-4

inverse

f (x) = 2 3 x - 4

\frac{x ^{3}}{8} + \frac{3 x ^{2}}{2} + 6 x + 8

Solution steps

y = 2 3 x - 4

Replace

x

with

y

x = 2 3 y - 4

Solve for

y, x = 2 3 y - 4

\frac{x ^{3}}{8} + \frac{3 x ^{2}}{2} + 6 x + 8

\frac{0.23 x}{x ^{2} + 25}

f (x) = sin (\frac{2 π x}{3} - 3 π)

f (x) = \frac{1}{2} x - 4

f (x) = \frac{x ^{3} + 5 x ^{2}}{7 x ^{2} - 3}

f (x) = - 4 cos (x) + 4

What is the inverse of f(x)=2\sqrt[3]{x}-4 ?
The inverse of f(x)=2\sqrt[3]{x}-4 is (x^3)/8+(3x^2)/2+6x+8