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Popular >

extreme y=x^2ln(x/4)

Solution

extreme points

y = x^{2} ln (\frac{x}{4})

Solution

Minimum (\frac{4}{e}, - \frac{8}{e})

Solution steps

f^{'} (x) = 2 x ln (\frac{x}{4}) + x

Find intervals:

Decreasing

: 0 < x < \frac{4}{e},

Increasing

: \frac{4}{e} < x < \infty

Plug

x = \frac{4}{e}

into

x^{2} ln (\frac{x}{4}) : - \frac{8}{e}

Minimum (\frac{4}{e}, - \frac{8}{e})

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Frequently Asked Questions (FAQ)

What is the extreme y=x^2ln(x/4) ?
The extreme y=x^2ln(x/4) is Minimum(4/(sqrt(e)),-8/e)