What is the inverse of f(x)=sqrt(x^2-25) ?

The inverse of f(x)=sqrt(x^2-25) is sqrt(x^2+25),-sqrt(x^2+25)

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inverse of f(x)=sqrt(x^2-25)

inverse

f (x) = x^{2} - 25

x^{2} + 25, - x^{2} + 25

Solution steps

y = x^{2} - 25

Replace

x

with

y

x = y^{2} - 25

Solve for

y, x = y^{2} - 25

x^{2} + 25, - x^{2} + 25

d o main x^{3} + x^{2} - 4 x - 4

in f l ec t i o n x

s hi f t y = 3 sin (π x - \frac{π}{3})

cr i t i c a l x^{6} (x - 1)^{5}

e x t re m e f (x) = - 2 x^{4} - 24 x^{3} - 10

What is the inverse of f(x)=sqrt(x^2-25) ?
The inverse of f(x)=sqrt(x^2-25) is sqrt(x^2+25),-sqrt(x^2+25)