What is the inverse of f(x)=(x+1)(x-2) ?

The inverse of f(x)=(x+1)(x-2) is (1+sqrt(4x+9))/2 ,(1-sqrt(4x+9))/2

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inverse of f(x)=(x+1)(x-2)

inverse

f (x) = (x + 1) (x - 2)

\frac{1 + 4 x + 9}{2}, \frac{1 - 4 x + 9}{2}

Solution steps

y = (x + 1) (x - 2)

Replace

x

with

y

x = (y + 1) (y - 2)

Solve for

y, x = (y + 1) (y - 2)

\frac{1 + 4 x + 9}{2}, \frac{1 - 4 x + 9}{2}

in v erse x^{3} - 12

d o main f (x) = \frac{( x + 2 )}{( x - 3 )}

p er p e n d i c u l a r 2 x + 3 y = 5

r an g e f (x) = - 4 x^{2} - 12 x

r an g e y = 9 x^{2}

What is the inverse of f(x)=(x+1)(x-2) ?
The inverse of f(x)=(x+1)(x-2) is (1+sqrt(4x+9))/2 ,(1-sqrt(4x+9))/2