What is the domain of-7/(2x^{3/2)} ?

The domain of-7/(2x^{3/2)} is x>0

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domain of-7/(2x^{3/2)}

domain

- \frac{7}{2 x ^{\frac{3}{2}}}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

r an g e f (x) = \frac{3 x + 6}{x - 1}

r an g e f (x) = \frac{( x + 3 )}{( x + 1 )}

d o main x + 9 + x + 8

l in e (- 3, 2), (2, - 6)

sy mm e t ry \frac{2 x ^{2} + 4 x - 6}{x ^{2} + 3 x - 10}