What is the domain of \sqrt[3]{1+sqrt(|x|-3)} ?

The domain of \sqrt[3]{1+sqrt(|x|-3)} is x = 3

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domain of \sqrt[3]{1+sqrt(|x|-3)}

domain

3 1 + ∣ x ∣ - 3

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

d o main f (x) = (2 x + 3) x^{2} + 8

a sy m pt o t es f (x) = 3 x + 2 - lo g_{e} (x^{2} - 1)

a sy m pt o t es f (x) = \frac{5 x + 7 x ^{4}}{4 - x ^{2}}

in v erse g (x) = 3^{x}

d o main f (x) = \frac{1}{2} (x + 3)^{2} - 2

What is the domain of \sqrt[3]{1+sqrt(|x|-3)} ?
The domain of \sqrt[3]{1+sqrt(|x|-3)} is x<=-3\lor x>= 3