What is the inverse of f(x)=-4+log_{2}(5-2x) ?

The inverse of f(x)=-4+log_{2}(5-2x) is -(2^{x+4}-5)/2

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inverse of f(x)=-4+log_{2}(5-2x)

inverse

f (x) = - 4 + lo g_{2} (5 - 2 x)

- \frac{2 ^{x + 4} - 5}{2}

Solution steps

y = - 4 + lo g_{2} (5 - 2 x)

Replace

x

with

y

x = - 4 + lo g_{2} (5 - 2 y)

Solve for

y, x = - 4 + lo g_{2} (5 - 2 y)

- \frac{2 ^{x + 4} - 5}{2}

e x t re m e 3 x^{5} - 5 x^{3} - 7

a sy m pt o t es \frac{x + 1}{x}

l in e (1, - 7), (2, - 1)

p a r i t y f (x) = x^{2} + 4 x

p er p e n d i c u l a r y = \frac{1}{8} x + 2

What is the inverse of f(x)=-4+log_{2}(5-2x) ?
The inverse of f(x)=-4+log_{2}(5-2x) is -(2^{x+4}-5)/2