What is the inverse of f(x)= 5/(\sqrt[3]{x-2)} ?

The inverse of f(x)= 5/(\sqrt[3]{x-2)} is (125)/(x^3)+2

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inverse of f(x)= 5/(\sqrt[3]{x-2)}

inverse

f (x) = \frac{5}{3 x - 2}

\frac{125}{x ^{3}} + 2

Solution steps

y = \frac{5}{3 x - 2}

Replace

x

with

y

x = \frac{5}{3 y - 2}

Solve for

y, x = \frac{5}{3 y - 2}

\frac{125}{x ^{3}} + 2

r an g e f (x) = (\frac{1}{8})^{x}

d o main f (x) = \frac{4}{1 - e ^{x}}

d o main \frac{4 - x}{x ( x - 3 )}

in t erce pt s y = - \frac{1}{4} x + 2

d o main - \frac{1}{2 7 - x}

What is the inverse of f(x)= 5/(\sqrt[3]{x-2)} ?
The inverse of f(x)= 5/(\sqrt[3]{x-2)} is (125)/(x^3)+2