What is the domain of f(x)=sqrt(3-x)*sqrt(x^2-1) ?

The domain of f(x)=sqrt(3-x)*sqrt(x^2-1) is x<=-1\lor 1<= x<= 3

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domain of f(x)=sqrt(3-x)*sqrt(x^2-1)

domain

f (x) = 3 - x \cdot x^{2} - 1

x \leq - 1 or 1 \leq x \leq 3

Interval Notation

(- \infty, - 1] \cup [1, 3]

Solution steps

Find non-negative values for radicals:

x \leq - 1 or 1 \leq x \leq 3

The function domain

x \leq - 1 or 1 \leq x \leq 3

in f l ec t i o n x^{4} - 5 x^{3} + x^{2} + 21 x - 18

d o main f (x) = \frac{3}{5 + x}

in t erce pt s \frac{( x + 6 ) ( x - 1 )}{( x - 1 ) ( x - 6 )}

d o main f (x) = arcsin (x)

e x t re m e g (x) = - 2 x^{4} + 8 x^{2} - 6

What is the domain of f(x)=sqrt(3-x)*sqrt(x^2-1) ?
The domain of f(x)=sqrt(3-x)*sqrt(x^2-1) is x<=-1\lor 1<= x<= 3