What is the perpendicular y=-4/3 x-8 ?

The perpendicular y=-4/3 x-8 is y= 3/4 x+b

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perpendicular y=-4/3 x-8

perpendicular

y = - \frac{4}{3} x - 8

y = \frac{3}{4} x + b

Solution steps

Find the slope of

y = - \frac{4}{3} x - 8 : m = - \frac{4}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{4}

Line with slope m=

\frac{3}{4} : y = \frac{3}{4} x + b

y = \frac{3}{4} x + b

in v erse h (x) = 7 x^{\frac{3}{5}}

d o main f (x) = (x - 2)^{2} - 9

sy mm e t ry y = (x + 7)^{3} - 2

in v erse 7 x - 9

d o main \frac{x - 1}{x + 4}

What is the perpendicular y=-4/3 x-8 ?
The perpendicular y=-4/3 x-8 is y= 3/4 x+b