What is the midpoint (-7/3 , 1/3),(-5/3 ,-7/3) ?

The midpoint (-7/3 , 1/3),(-5/3 ,-7/3) is (-2,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

midpoint (-7/3 , 1/3),(-5/3 ,-7/3)

midpoint

(- \frac{7}{3}, \frac{1}{3}), (- \frac{5}{3}, - \frac{7}{3})

(- 2, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- \frac{7}{3}, \frac{1}{3}), (x_{2}, y_{2}) = (- \frac{5}{3}, - \frac{7}{3})

= (\frac{- \frac{5}{3} - \frac{7}{3}}{2}, \frac{- \frac{7}{3} + \frac{1}{3}}{2})

Refine

= (- 2, - 1)

d o main 5 + x

in t erce pt s f (x) = \frac{2 x + 3}{x + 4}

d i s t an ce (- 1, - 9), (6, 8)

d o main f (x) = lo g_{5} (8 - 2 x)

e x t re m e f (x) = x^{3} - 6 x^{2} - 135 x

What is the midpoint (-7/3 , 1/3),(-5/3 ,-7/3) ?
The midpoint (-7/3 , 1/3),(-5/3 ,-7/3) is (-2,-1)