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Popular Functions >

range of f(x)=x^2-8x

Solution

range

f (x) = x^{2} - 8 x

Solution

f (x) \geq - 16

+1

Interval Notation

[- 16, \infty)

Solution steps

Vertex of

x^{2} - 8 x :

Minimum

(4, - 16)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (4, - 16)

f (x) \geq - 16

Graph

Popular Examples

range of sqrt(x^2-16)

r an g e x^{2} - 16

distance (0,0),(0.15,1.9621)

d i s t an ce (0, 0), (0.15, 1.9621)

domain of e^{sqrt(x+x^2)}

d o main e^{x + x^{2}}

inverse of y=(3x)/(x-2)

in v erse y = \frac{3 x}{x - 2}

inverse of f(x)=4^{3x-1}

in v erse f (x) = 4^{3 x - 1}

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2-8x ?
The range of f(x)=x^2-8x is f(x)>=-16