What is the inverse of 2x^2+3x-20 ?

The inverse of 2x^2+3x-20 is (-3+sqrt(8x+169))/4 ,(-3-sqrt(8x+169))/4

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inverse of 2x^2+3x-20

inverse

2 x^{2} + 3 x - 20

\frac{- 3 + 8 x + 169}{4}, \frac{- 3 - 8 x + 169}{4}

Solution steps

y = 2 x^{2} + 3 x - 20

Replace

x

with

y

x = 2 y^{2} + 3 y - 20

Solve for

y, x = 2 y^{2} + 3 y - 20

\frac{- 3 + 8 x + 169}{4}, \frac{- 3 - 8 x + 169}{4}

e x t re m e f (x) = \frac{x}{x ^{2} - x + 1}

in v erse 3 5 x - 2

r an g e f (x) = - x^{2} + 6 x - 5

in v erse f (x) = (19 - t)^{\frac{1}{2}}

in v erse x^{2} - 14

What is the inverse of 2x^2+3x-20 ?
The inverse of 2x^2+3x-20 is (-3+sqrt(8x+169))/4 ,(-3-sqrt(8x+169))/4