What is the domain of u(x)=sqrt(x+1) ?

The domain of u(x)=sqrt(x+1) is x>=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of u(x)=sqrt(x+1)

domain

u (x) = x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

d o main f (x) = 6 x + 6

s l o p e 6 x + 3 y = - 9

in v erse 3 - 2 x

d o main f (x) = \frac{( x - 4 ) ( x - 8 )}{x - 5}

in v erse f (x) = \frac{- 2 x + 1}{3}