What is the inverse of \sqrt[5]{x}-2 ?

The inverse of \sqrt[5]{x}-2 is x^5+10x^4+40x^3+80x^2+80x+32

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of \sqrt[5]{x}-2

inverse

5 x - 2

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 32

Solution steps

y = 5 x - 2

Replace

x

with

y

x = 5 y - 2

Solve for

y, x = 5 y - 2

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 32

in v erse 10

d o main f (x) = (x - 6)

d o main f (x) = \frac{1}{x + 3} + 2

in v erse 3 x + 12

e x t re m e f (x) = - x^{2} + 3 x, - 1 \leq x \leq 3

What is the inverse of \sqrt[5]{x}-2 ?
The inverse of \sqrt[5]{x}-2 is x^5+10x^4+40x^3+80x^2+80x+32