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Popular Functions >

midpoint (m,c),(0,0)

Solution

midpoint

(m, c), (0, 0)

Solution

(\frac{m}{2}, \frac{c}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (m, c), (x_{2}, y_{2}) = (0, 0)

= (\frac{0 + m}{2}, \frac{0 + c}{2})

Refine

= (\frac{m}{2}, \frac{c}{2})

Graph

Popular Examples

range of (x^2)/(x+1)

r an g e \frac{x ^{2}}{x + 1}

intercepts of f(x)=x^2-x-5

in t erce pt s f (x) = x^{2} - x - 5

domain of 7/((2*sqrt(9+7x)))

d o main \frac{7}{( 2 \cdot 9 + 7 x )}

inverse of y=log_{5}(x)

in v erse y = lo g_{5} (x)

domain of-(x+5)/7

d o main - \frac{x + 5}{7}

Frequently Asked Questions (FAQ)

What is the midpoint (m,c),(0,0) ?
The midpoint (m,c),(0,0) is (m/2 , c/2)