What is the inverse of f(x)=-x^2-2,x>= 0 ?

The inverse of f(x)=-x^2-2,x>= 0 is sqrt(-x-2),-sqrt(-x-2)

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inverse of f(x)=-x^2-2,x>= 0

inverse

f (x) = - x^{2} - 2, x \geq 0

- x - 2, - - x - 2

Solution steps

y = - x^{2} - 2

Replace

x

with

y

x = - y^{2} - 2

Solve for

y, x = - y^{2} - 2

- x - 2, - - x - 2

\frac{10}{1 - x}

\frac{1}{4} x^{2}

\frac{x - 1}{x ^{2}}

y = - 2 x

f (x) = 2 x

What is the inverse of f(x)=-x^2-2,x>= 0 ?
The inverse of f(x)=-x^2-2,x>= 0 is sqrt(-x-2),-sqrt(-x-2)